While we are on the subject of Attack Multiple opponents. How does it really work?
Say that Mizuchi is in BtB with two bakemonos. He activates and attacks both with his tail swipe.
Does he first fight one round (attack and counterattack) vs. Wu and then one against Po? Or does he first make both his attacks vs. each of them before they get to retiliate?
I suppose both Wu and Po tires by this attack.
Now let's look at Kenko, who was (singularily ineffectively) attacked by Wu, and is now charged by Po. He decides to attack both.
What order will the combat be in?
Does it tire Wu that he is embroiled in another fight?
Does Wu count as attacker or defender, i.e. does he strike first or last? No, wait, I just realised the answer to that by RtFM: It is the active player who strikes first!
He first fights one round (attack and counterattack) vs. Wu and then one against Po. After which everyone who fought tires. He needs to put at least one dice in his pool and split the pools before resolving any of the Melee exchanges.
In essense the model fights as many Melee exchanges with the same action but the splits the base pool before each Melee is resolved.
"To a real warrior, power perceived may be power achieved."
Thanks!
Who decides the order of the sub-melees? The active player seems like the obvious choice to me.
I follow the rules of bushido. I am a bushi.
Correct the player "Attacking multiple opponents" decides.
"To a real warrior, power perceived may be power achieved."
Uhm, am I correct? But the player 'Attacking multiple opponents' need not be the active player.
I follow the rules of bushido. I am a bushi.
Yes
"To a real warrior, power perceived may be power achieved."
Sorry to get this thing back, but I need a little bit more of information, sorry.
Let's get some examples.
1.- Kenko (nos exhausted) already enganged with wu, now charged by po. He allocates two dice on every bakemono, so kenko vs wu: 2 dice vs 1 dice, then 2 kenko vs po: 2 dice versus 1 dice, or the same in the opposite order, as the bakemono player decides. And everybody exhausted. Is it correct?
2.- After the previous situatios, fe decides join the party, and charge kenko too. Kenko is now exhausted and has only tree dice, so he decides to split them one dice per bakemono. The Savage Wave player chooses the order of the melees, but let's suposse he decides fe - wu - po. So kenko vs fe: 1 die vs 1 die; kenko vs wu: 2 dice (since wu is exhausted) vs 1 die; finally kenko vs po: 2 vs 1. Is it right too?
3.- Not an example, but a final question XD: Must all this dice (in the last example) have been already allocated as defence or attack dice before any fight is performed, or you just take the decision for every fight once the moment comes?
Thanks a lot for the extra clarifications, it's that I like to be pretty sure about the rules when I play a game. XD
1. From what Master T says it's Kenko who decides which sub-fight is fought first, being the one who splits his attack. Everybody's exhausted provided Kenko and Wu were tired before Po joined in the fun.
2. Kenko does not need to attack all three, he can fight just one, two or all three as he wishes. He also decides the order. (Also, he only has two dice - three enemies do outnumber him, even if two do not - so he cannot split in three.)
3. It it is three separate melees, fought consecutively. You decide attack defence as they come.
I follow the rules of bushido. I am a bushi.
Oh, right, the model with the Multiple thing decides.
Thanks a lot for the answer.
Just a tiny doubt more: Kenko is unoutnumbered (2) per faq, so if I get it (I'm not sure of anything so soon XD), he doesn't lose the first outnumbered die until he fights 4 models, does he?
You are both wrong, as you may only decide to Attack Mulltiple opponents if you are the Active model.
When you are the Active model and in BtB with more than one enemy model you MAY choose to split your CP between the models providing that you can assign at least one dice to each model you want to fight.
Then resolve the Melee's in the order you choose and after all the Melees are resolved Tired each model involved (the Attack Multiple opponents model only tires once)
Attack Multiple opponents (2) means that there needs to be more than 2 enemies counting for Outnumbering to start inflicting a penalty.
"To a real warrior, power perceived may be power achieved."
Ooook, thanks a lot.
I thing I understand it now!
:)
Your laconical answers have confused me once again T.
Simply answering 'Yes' to a complex question isn't always helpful, in particular if there's nothing earlier said, as far as I can see, about having to be active to use AMO.
I follow the rules of bushido. I am a bushi.
Oops it was probably late when I answered. When you Charge or melee you need a target. The in-active model is the target and so can't target another in-active model. So you can't use AMO when not the Actice model. Sorry for confusion.
"To a real warrior, power perceived may be power achieved."
Thanks!
I see now, and it does actually state 'may split their CP and initiate a Melee combat'. That wasn't clear enough for confusians like me, though.
I follow the rules of bushido. I am a bushi.